Nośność muru parteru wg modelu ciągłego.

M_{pd}  =  - \frac{1}
{{12}} \cdot q_d  \cdot l_r ^2 

q_d  = (g + p)_d  = g_{1k}  \cdot \gamma _{fg}  + g_{2k}  \cdot \gamma _{fg}  + g_{3k}  \cdot \gamma _{fg}  + p_k  \cdot \gamma _{fp} 

q_d  = 1,50 \cdot 1,35 + 2,96 \cdot 1,35 + 1,70 \cdot 1,35 + 3,00 \cdot 1,50 = 12,82kN/m

M_{pd}  =  - \frac{1}
{{12}} \cdot 12,82 \cdot 6,20^2  =  - 41,07kNm/1m

\frac{{E_{cm}  \cdot I_r }}
{{l_r }} = \frac{{29 \cdot 10^6  \cdot \frac{{1,0 \cdot 0,24^3 }}
{{12}}}}
{{6,20}} = 5388kNm

\frac{{E_m  \cdot I_{1m} }}
{{h_1 }} = \frac{{E_m  \cdot I_{2m} }}
{{h_2 }} = \frac{{E_m  \cdot I_m }}
{{h_k }}

\frac{{E_m  \cdot I_{1m} }}
{{h_1 }} = \frac{{E_m  \cdot I_{2m} }}
{{h_2 }} = \frac{{E_m  \cdot I_m }}
{{h_k }} = 690 \cdot 4,9 \cdot 10^3  \cdot \frac{{\frac{{1,0 \cdot 0,38^3 }}
{{12}}}}
{{3,60}} = 4294kNm

M_{1d}  = M_{2d}  = 0,85 \cdot 41,07 \cdot \frac{{4294}}
{{4294 + 4294 + 5388}} = 10,73kNm/1m

M_{1wd}  = M_{wd}  = \frac{1}
{{16}} \cdot Wk \cdot h_k ^2  \cdot \gamma _f  \cdot \psi _{01}  = \frac{1}
{{16}} \cdot 1,158 \cdot 3,60^2  \cdot 1,50 \cdot 0,6 = 0,84kNm

e_a  = \max \left\{ \begin{gathered}
  \frac{h}
{{300}}  \\
  10mm \ \\ 
\end{gathered}  \right.

e_a  = \max \left\{ \begin{gathered}
  \frac{{360 - 24}}
{{300}} = 11,2mm \ \\
  10mm \ \\ 
\end{gathered}  \right.